PERLRE(1) Perl Programmers Reference Guide PERLRE(1)
NAME
perlre - Perl regular expressions
DESCRIPTION
This page describes the syntax of regular expressions in
Perl. For a description of how to use regular expressions
in matching operations, plus various examples of the same,
see discussion of m//, s///, qr// and ?? in the section on
Regexp Quote-Like Operators in the perlop manpage.
The matching operations can have various modifiers. The
modifiers that relate to the interpretation of the regular
expression inside are listed below. For the modifiers
that alter the way a regular expression is used by Perl,
see the section on Regexp Quote-Like Operators in the
perlop manpage and the section on Gory details of parsing
quoted constructs in the perlop manpage.
i Do case-insensitive pattern matching.
If use locale is in effect, the case map is taken from
the current locale. See the perllocale manpage.
m Treat string as multiple lines. That is, change "^"
and "$" from matching at only the very start or end of
the string to the start or end of any line anywhere
within the string,
s Treat string as single line. That is, change "." to
match any character whatsoever, even a newline, which
it normally would not match.
The /s and /m modifiers both override the $* setting.
That is, no matter what $* contains, /s without /m
will force "^" to match only at the beginning of the
string and "$" to match only at the end (or just
before a newline at the end) of the string. Together,
as /ms, they let the "." match any character
whatsoever, while yet allowing "^" and "$" to match,
respectively, just after and just before newlines
within the string.
x Extend your pattern's legibility by permitting
whitespace and comments.
These are usually written as "the /x modifier", even
though the delimiter in question might not actually be a
slash. In fact, any of these modifiers may also be
embedded within the regular expression itself using the
new (?...) construct. See below.
The /x modifier itself needs a little more explanation.
It tells the regular expression parser to ignore
whitespace that is neither backslashed nor within a
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character class. You can use this to break up your
regular expression into (slightly) more readable parts.
The # character is also treated as a metacharacter
introducing a comment, just as in ordinary Perl code.
This also means that if you want real whitespace or #
characters in the pattern (outside of a character class,
where they are unaffected by /x), that you'll either have
to escape them or encode them using octal or hex escapes.
Taken together, these features go a long way towards
making Perl's regular expressions more readable. Note
that you have to be careful not to include the pattern
delimiter in the comment--perl has no way of knowing you
did not intend to close the pattern early. See the
C-comment deletion code in the perlop manpage.
Regular Expressions
The patterns used in pattern matching are regular
expressions such as those supplied in the Version 8 regex
routines. (In fact, the routines are derived (distantly)
from Henry Spencer's freely redistributable
reimplementation of the V8 routines.) See the section on
Version 8 Regular Expressions for details.
In particular the following metacharacters have their
standard egrep-ish meanings:
\ Quote the next metacharacter
^ Match the beginning of the line
. Match any character (except newline)
$ Match the end of the line (or before newline at the end)
| Alternation
() Grouping
[] Character class
By default, the "^" character is guaranteed to match at
only the beginning of the string, the "$" character at
only the end (or before the newline at the end) and Perl
does certain optimizations with the assumption that the
string contains only one line. Embedded newlines will not
be matched by "^" or "$". You may, however, wish to treat
a string as a multi-line buffer, such that the "^" will
match after any newline within the string, and "$" will
match before any newline. At the cost of a little more
overhead, you can do this by using the /m modifier on the
pattern match operator. (Older programs did this by
setting $*, but this practice is now deprecated.)
To facilitate multi-line substitutions, the "." character
never matches a newline unless you use the /s modifier,
which in effect tells Perl to pretend the string is a
single line--even if it isn't. The /s modifier also
overrides the setting of $*, in case you have some (badly
behaved) older code that sets it in another module.
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The following standard quantifiers are recognized:
* Match 0 or more times
+ Match 1 or more times
? Match 1 or 0 times
{n} Match exactly n times
{n,} Match at least n times
{n,m} Match at least n but not more than m times
(If a curly bracket occurs in any other context, it is
treated as a regular character.) The "*" modifier is
equivalent to {0,}, the "+" modifier to {1,}, and the "?"
modifier to {0,1}. n and m are limited to integral values
less than a preset limit defined when perl is built. This
is usually 32766 on the most common platforms. The actual
limit can be seen in the error message generated by code
such as this:
$_ **= $_ , / {$_} / for 2 .. 42;
By default, a quantified subpattern is "greedy", that is,
it will match as many times as possible (given a
particular starting location) while still allowing the
rest of the pattern to match. If you want it to match the
minimum number of times possible, follow the quantifier
with a "?". Note that the meanings don't change, just the
"greediness":
*? Match 0 or more times
+? Match 1 or more times
?? Match 0 or 1 time
{n}? Match exactly n times
{n,}? Match at least n times
{n,m}? Match at least n but not more than m times
Because patterns are processed as double quoted strings,
the following also work:
\t tab (HT, TAB)
\n newline (LF, NL)
\r return (CR)
\f form feed (FF)
\a alarm (bell) (BEL)
\e escape (think troff) (ESC)
\033 octal char (think of a PDP-11)
\x1B hex char
\c[ control char
\l lowercase next char (think vi)
\u uppercase next char (think vi)
\L lowercase till \E (think vi)
\U uppercase till \E (think vi)
\E end case modification (think vi)
\Q quote (disable) pattern metacharacters till \E
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If use locale is in effect, the case map used by \l, \L,
\u and \U is taken from the current locale. See the
perllocale manpage.
You cannot include a literal $ or @ within a \Q sequence.
An unescaped $ or @ interpolates the corresponding
variable, while escaping will cause the literal string \$
to be matched. You'll need to write something like
m/\Quser\E\@\Qhost/.
In addition, Perl defines the following:
\w Match a "word" character (alphanumeric plus "_")
\W Match a non-word character
\s Match a whitespace character
\S Match a non-whitespace character
\d Match a digit character
\D Match a non-digit character
A \w matches a single alphanumeric character, not a whole
word. To match a word you'd need to say \w+. If use
locale is in effect, the list of alphabetic characters
generated by \w is taken from the current locale. See the
perllocale manpage. You may use \w, \W, \s, \S, \d, and \D
within character classes (though not as either end of a
range).
Perl defines the following zero-width assertions:
\b Match a word boundary
\B Match a non-(word boundary)
\A Match only at beginning of string
\Z Match only at end of string, or before newline at the end
\z Match only at end of string
\G Match only where previous m//g left off (works only with /g)
A word boundary (\b) is defined as a spot between two
characters that has a \w on one side of it and a \W on the
other side of it (in either order), counting the imaginary
characters off the beginning and end of the string as
matching a \W. (Within character classes \b represents
backspace rather than a word boundary.) The \A and \Z are
just like "^" and "$", except that they won't match
multiple times when the /m modifier is used, while "^" and
"$" will match at every internal line boundary. To match
the actual end of the string, not ignoring newline, you
can use \z. The \G assertion can be used to chain global
matches (using m//g), as described in the section on
Regexp Quote-Like Operators in the perlop manpage.
It is also useful when writing lex-like scanners, when you
have several patterns that you want to match against
consequent substrings of your string, see the previous
reference. The actual location where \G will match can
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also be influenced by using pos() as an lvalue. See the
pos entry in the perlfunc manpage.
When the bracketing construct ( ... ) is used, \<digit>
matches the digit'th substring. Outside of the pattern,
always use "$" instead of "\" in front of the digit.
(While the \<digit> notation can on rare occasion work
outside the current pattern, this should not be relied
upon. See the WARNING below.) The scope of $<digit> (and
$`, $&, and $') extends to the end of the enclosing BLOCK
or eval string, or to the next successful pattern match,
whichever comes first. If you want to use parentheses to
delimit a subpattern (e.g., a set of alternatives) without
saving it as a subpattern, follow the ( with a ?:.
You may have as many parentheses as you wish. If you have
more than 9 substrings, the variables $10, $11, ... refer
to the corresponding substring. Within the pattern, \10,
\11, etc. refer back to substrings if there have been at
least that many left parentheses before the backreference.
Otherwise (for backward compatibility) \10 is the same as
\010, a backspace, and \11 the same as \011, a tab. And
so on. (\1 through \9 are always backreferences.)
$+ returns whatever the last bracket match matched. $&
returns the entire matched string. ($0 used to return the
same thing, but not any more.) $` returns everything
before the matched string. $' returns everything after
the matched string. Examples:
s/^([^ ]*) *([^ ]*)/$2 $1/; # swap first two words
if (/Time: (..):(..):(..)/) {
$hours = $1;
$minutes = $2;
$seconds = $3;
}
Once perl sees that you need one of $&, $` or $' anywhere
in the program, it has to provide them on each and every
pattern match. This can slow your program down. The same
mechanism that handles these provides for the use of $1,
$2, etc., so you pay the same price for each pattern that
contains capturing parentheses. But if you never use $&,
etc., in your script, then patterns without capturing
parentheses won't be penalized. So avoid $&, $', and $` if
you can, but if you can't (and some algorithms really
appreciate them), once you've used them once, use them at
will, because you've already paid the price. As of 5.005,
$& is not so costly as the other two.
Backslashed metacharacters in Perl are alphanumeric, such
as \b, \w, \n. Unlike some other regular expression
languages, there are no backslashed symbols that aren't
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alphanumeric. So anything that looks like \\, \(, \), \<,
\>, \{, or \} is always interpreted as a literal
character, not a metacharacter. This was once used in a
common idiom to disable or quote the special meanings of
regular expression metacharacters in a string that you
want to use for a pattern. Simply quote all non-
alphanumeric characters:
$pattern =~ s/(\W)/\\$1/g;
Now it is much more common to see either the quotemeta()
function or the \Q escape sequence used to disable all
metacharacters' special meanings like this:
/$unquoted\Q$quoted\E$unquoted/
Perl defines a consistent extension syntax for regular
expressions. The syntax is a pair of parentheses with a
question mark as the first thing within the parentheses
(this was a syntax error in older versions of Perl). The
character after the question mark gives the function of
the extension. Several extensions are already supported:
(?#text) A comment. The text is ignored. If the /x
switch is used to enable whitespace formatting,
a simple # will suffice. Note that perl closes
the comment as soon as it sees a ), so there is
no way to put a literal ) in the comment.
(?:pattern)
(?imsx-imsx:pattern)
This is for clustering, not capturing; it groups
subexpressions like "()", but doesn't make
backreferences as "()" does. So
@fields = split(/\b(?:a|b|c)\b/)
is like
@fields = split(/\b(a|b|c)\b/)
but doesn't spit out extra fields.
The letters between ? and : act as flags
modifiers, see the (?imsx-imsx) manpage. In
particular,
/(?s-i:more.*than).*million/i
is equivalent to more verbose
/(?:(?s-i)more.*than).*million/i
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(?=pattern)
A zero-width positive lookahead assertion. For
example, /\w+(?=\t)/ matches a word followed by
a tab, without including the tab in $&.
(?!pattern)
A zero-width negative lookahead assertion. For
example /foo(?!bar)/ matches any occurrence of
"foo" that isn't followed by "bar". Note
however that lookahead and lookbehind are NOT
the same thing. You cannot use this for
lookbehind.
If you are looking for a "bar" that isn't
preceded by a "foo", /(?!foo)bar/ will not do
what you want. That's because the (?!foo) is
just saying that the next thing cannot be
"foo"--and it's not, it's a "bar", so "foobar"
will match. You would have to do something like
/(?!foo)...bar/ for that. We say "like"
because there's the case of your "bar" not
having three characters before it. You could
cover that this way:
/(?:(?!foo)...|^.{0,2})bar/. Sometimes it's
still easier just to say:
if (/bar/ && $` !~ /foo$/)
For lookbehind see below.
(?<=pattern)
A zero-width positive lookbehind assertion. For
example, /(?<=\t)\w+/ matches a word following a
tab, without including the tab in $&. Works
only for fixed-width lookbehind.
(?<!pattern)
A zero-width negative lookbehind assertion. For
example /(?<!bar)foo/ matches any occurrence of
"foo" that isn't following "bar". Works only
for fixed-width lookbehind.
(?{ code })
Experimental "evaluate any Perl code" zero-width
assertion. Always succeeds. code is not
interpolated. Currently the rules to determine
where the code ends are somewhat convoluted.
The code is properly scoped in the following
sense: if the assertion is backtracked (compare
the section on Backtracking), all the changes
introduced after localisation are undone, so
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$_ = 'a' x 8;
m<
(?{ $cnt = 0 }) # Initialize $cnt.
(
a
(?{
local $cnt = $cnt + 1; # Update $cnt, backtracking-safe.
})
)*
aaaa
(?{ $res = $cnt }) # On success copy to non-localized
# location.
>x;
will set $res = 4. Note that after the match
$cnt returns to the globally introduced value 0,
since the scopes which restrict local statements
are unwound.
This assertion may be used as (?(condition)yes-
pattern switch. If not used in this way, the
result of evaluation of code is put into
variable $^R. This happens immediately, so $^R
can be used from other (?{ code }) assertions
inside the same regular expression.
The above assignment to $^R is properly
localized, thus the old value of $^R is restored
if the assertion is backtracked (compare the
section on Backtracking).
Due to security concerns, this construction is
not allowed if the regular expression involves
run-time interpolation of variables, unless use
re 'eval' pragma is used (see the re manpage),
or the variables contain results of qr()
operator (see the section on qr/STRING/imosx in
the perlop manpage).
This restriction is due to the wide-spread
(questionable) practice of using the construct
$re = <>;
chomp $re;
$string =~ /$re/;
without tainting. While this code is frowned
upon from security point of view, when (?{}) was
introduced, it was considered bad to add new
security holes to existing scripts.
NOTE: Use of the above insecure snippet without
also enabling taint mode is to be severely
frowned upon. use re 'eval' does not disable
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tainting checks, thus to allow $re in the above
snippet to contain (?{}) with tainting enabled,
one needs both use re 'eval' and untaint the
$re.
(?>pattern)
An "independent" subexpression. Matches the
substring that a standalone pattern would match
if anchored at the given position, and only this
substring.
Say, ^(?>a*)ab will never match, since (?>a*)
(anchored at the beginning of string, as above)
will match all characters a at the beginning of
string, leaving no a for ab to match. In
contrast, a*ab will match the same as a+b, since
the match of the subgroup a* is influenced by
the following group ab (see the section on
Backtracking). In particular, a* inside a*ab
will match fewer characters than a standalone
a*, since this makes the tail match.
An effect similar to (?>pattern) may be achieved
by
(?=(pattern))\1
since the lookahead is in "logical" context,
thus matches the same substring as a standalone
a+. The following \1 eats the matched string,
thus making a zero-length assertion into an
analogue of (?>...). (The difference between
these two constructs is that the second one uses
a catching group, thus shifting ordinals of
backreferences in the rest of a regular
expression.)
This construct is useful for optimizations of
"eternal" matches, because it will not backtrack
(see the section on Backtracking).
m{ \(
(
[^()]+
|
\( [^()]* \)
)+
\)
}x
That will efficiently match a nonempty group
with matching two-or-less-level-deep
parentheses. However, if there is no such
group, it will take virtually forever on a long
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string. That's because there are so many
different ways to split a long string into
several substrings. This is what (.+)+ is
doing, and (.+)+ is similar to a subpattern of
the above pattern. Consider that the above
pattern detects no-match on
((()aaaaaaaaaaaaaaaaaa in several seconds, but
that each extra letter doubles this time. This
exponential performance will make it appear that
your program has hung.
However, a tiny modification of this pattern
m{ \(
(
(?> [^()]+ )
|
\( [^()]* \)
)+
\)
}x
which uses (?>...) matches exactly when the one
above does (verifying this yourself would be a
productive exercise), but finishes in a fourth
the time when used on a similar string with
1000000 as. Be aware, however, that this
pattern currently triggers a warning message
under -w saying it "matches the null string many
times"):
On simple groups, such as the pattern (?> [^()]+
), a comparable effect may be achieved by
negative lookahead, as in [^()]+ (?! [^()] ).
This was only 4 times slower on a string with
1000000 as.
(?(condition)yes-pattern|no-pattern)
(?(condition)yes-pattern)
Conditional expression. (condition) should be
either an integer in parentheses (which is valid
if the corresponding pair of parentheses
matched), or lookahead/lookbehind/evaluate zero-
width assertion.
Say,
m{ ( \( )?
[^()]+
(?(1) \) )
}x
matches a chunk of non-parentheses, possibly
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included in parentheses themselves.
(?imsx-imsx)
One or more embedded pattern-match modifiers.
This is particularly useful for patterns that
are specified in a table somewhere, some of
which want to be case sensitive, and some of
which don't. The case insensitive ones need to
include merely (?i) at the front of the pattern.
For example:
$pattern = "foobar";
if ( /$pattern/i ) { }
# more flexible:
$pattern = "(?i)foobar";
if ( /$pattern/ ) { }
Letters after - switch modifiers off.
These modifiers are localized inside an
enclosing group (if any). Say,
( (?i) blah ) \s+ \1
(assuming x modifier, and no i modifier outside
of this group) will match a repeated (including
the case!) word blah in any case.
A question mark was chosen for this and for the new
minimal-matching construct because 1) question mark is
pretty rare in older regular expressions, and 2) whenever
you see one, you should stop and "question" exactly what
is going on. That's psychology...
Backtracking
A fundamental feature of regular expression matching
involves the notion called backtracking, which is
currently used (when needed) by all regular expression
quantifiers, namely *, *?, +, +?, {n,m}, and {n,m}?.
For a regular expression to match, the entire regular
expression must match, not just part of it. So if the
beginning of a pattern containing a quantifier succeeds in
a way that causes later parts in the pattern to fail, the
matching engine backs up and recalculates the beginning
part--that's why it's called backtracking.
Here is an example of backtracking: Let's say you want to
find the word following "foo" in the string "Food is on
the foo table.":
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$_ = "Food is on the foo table.";
if ( /\b(foo)\s+(\w+)/i ) {
print "$2 follows $1.\n";
}
When the match runs, the first part of the regular
expression (\b(foo)) finds a possible match right at the
beginning of the string, and loads up $1 with "Foo".
However, as soon as the matching engine sees that there's
no whitespace following the "Foo" that it had saved in $1,
it realizes its mistake and starts over again one
character after where it had the tentative match. This
time it goes all the way until the next occurrence of
"foo". The complete regular expression matches this time,
and you get the expected output of "table follows foo."
Sometimes minimal matching can help a lot. Imagine you'd
like to match everything between "foo" and "bar".
Initially, you write something like this:
$_ = "The food is under the bar in the barn.";
if ( /foo(.*)bar/ ) {
print "got <$1>\n";
}
Which perhaps unexpectedly yields:
got <d is under the bar in the >
That's because .* was greedy, so you get everything
between the first "foo" and the last "bar". In this case,
it's more effective to use minimal matching to make sure
you get the text between a "foo" and the first "bar"
thereafter.
if ( /foo(.*?)bar/ ) { print "got <$1>\n" }
got <d is under the >
Here's another example: let's say you'd like to match a
number at the end of a string, and you also want to keep
the preceding part the match. So you write this:
$_ = "I have 2 numbers: 53147";
if ( /(.*)(\d*)/ ) { # Wrong!
print "Beginning is <$1>, number is <$2>.\n";
}
That won't work at all, because .* was greedy and gobbled
up the whole string. As \d* can match on an empty string
the complete regular expression matched successfully.
Beginning is <I have 2 numbers: 53147>, number is <>.
Here are some variants, most of which don't work:
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$_ = "I have 2 numbers: 53147";
@pats = qw{
(.*)(\d*)
(.*)(\d+)
(.*?)(\d*)
(.*?)(\d+)
(.*)(\d+)$
(.*?)(\d+)$
(.*)\b(\d+)$
(.*\D)(\d+)$
};
for $pat (@pats) {
printf "%-12s ", $pat;
if ( /$pat/ ) {
print "<$1> <$2>\n";
} else {
print "FAIL\n";
}
}
That will print out:
(.*)(\d*) <I have 2 numbers: 53147> <>
(.*)(\d+) <I have 2 numbers: 5314> <7>
(.*?)(\d*) <> <>
(.*?)(\d+) <I have > <2>
(.*)(\d+)$ <I have 2 numbers: 5314> <7>
(.*?)(\d+)$ <I have 2 numbers: > <53147>
(.*)\b(\d+)$ <I have 2 numbers: > <53147>
(.*\D)(\d+)$ <I have 2 numbers: > <53147>
As you see, this can be a bit tricky. It's important to
realize that a regular expression is merely a set of
assertions that gives a definition of success. There may
be 0, 1, or several different ways that the definition
might succeed against a particular string. And if there
are multiple ways it might succeed, you need to understand
backtracking to know which variety of success you will
achieve.
When using lookahead assertions and negations, this can
all get even tricker. Imagine you'd like to find a
sequence of non-digits not followed by "123". You might
try to write that as
$_ = "ABC123";
if ( /^\D*(?!123)/ ) { # Wrong!
print "Yup, no 123 in $_\n";
}
But that isn't going to match; at least, not the way
you're hoping. It claims that there is no 123 in the
string. Here's a clearer picture of why it that pattern
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matches, contrary to popular expectations:
$x = 'ABC123' ;
$y = 'ABC445' ;
print "1: got $1\n" if $x =~ /^(ABC)(?!123)/ ;
print "2: got $1\n" if $y =~ /^(ABC)(?!123)/ ;
print "3: got $1\n" if $x =~ /^(\D*)(?!123)/ ;
print "4: got $1\n" if $y =~ /^(\D*)(?!123)/ ;
This prints
2: got ABC
3: got AB
4: got ABC
You might have expected test 3 to fail because it seems to
a more general purpose version of test 1. The important
difference between them is that test 3 contains a
quantifier (\D*) and so can use backtracking, whereas test
1 will not. What's happening is that you've asked "Is it
true that at the start of $x, following 0 or more non-
digits, you have something that's not 123?" If the
pattern matcher had let \D* expand to "ABC", this would
have caused the whole pattern to fail. The search engine
will initially match \D* with "ABC". Then it will try to
match (?!123 with "123", which of course fails. But
because a quantifier (\D*) has been used in the regular
expression, the search engine can backtrack and retry the
match differently in the hope of matching the complete
regular expression.
The pattern really, really wants to succeed, so it uses
the standard pattern back-off-and-retry and lets \D*
expand to just "AB" this time. Now there's indeed
something following "AB" that is not "123". It's in fact
"C123", which suffices.
We can deal with this by using both an assertion and a
negation. We'll say that the first part in $1 must be
followed by a digit, and in fact, it must also be followed
by something that's not "123". Remember that the
lookaheads are zero-width expressions--they only look, but
don't consume any of the string in their match. So
rewriting this way produces what you'd expect; that is,
case 5 will fail, but case 6 succeeds:
print "5: got $1\n" if $x =~ /^(\D*)(?=\d)(?!123)/ ;
print "6: got $1\n" if $y =~ /^(\D*)(?=\d)(?!123)/ ;
6: got ABC
In other words, the two zero-width assertions next to each
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other work as though they're ANDed together, just as you'd
use any builtin assertions: /^$/ matches only if you're
at the beginning of the line AND the end of the line
simultaneously. The deeper underlying truth is that
juxtaposition in regular expressions always means AND,
except when you write an explicit OR using the vertical
bar. /ab/ means match "a" AND (then) match "b", although
the attempted matches are made at different positions
because "a" is not a zero-width assertion, but a one-width
assertion.
One warning: particularly complicated regular expressions
can take exponential time to solve due to the immense
number of possible ways they can use backtracking to try
match. For example this will take a very long time to run
/((a{0,5}){0,5}){0,5}/
And if you used *'s instead of limiting it to 0 through 5
matches, then it would take literally forever--or until
you ran out of stack space.
A powerful tool for optimizing such beasts is
"independent" groups, which do not backtrace (see the
(?>pattern) manpage). Note also that zero-length
lookahead/lookbehind assertions will not backtrace to make
the tail match, since they are in "logical" context: only
the fact whether they match or not is considered relevant.
For an example where side-effects of a lookahead might
have influenced the following match, see the (?>pattern)
manpage.
Version 8 Regular Expressions
In case you're not familiar with the "regular" Version 8
regex routines, here are the pattern-matching rules not
described above.
Any single character matches itself, unless it is a
metacharacter with a special meaning described here or
above. You can cause characters that normally function as
metacharacters to be interpreted literally by prefixing
them with a "\" (e.g., "\." matches a ".", not any
character; "\\" matches a "\"). A series of characters
matches that series of characters in the target string, so
the pattern blurfl would match "blurfl" in the target
string.
You can specify a character class, by enclosing a list of
characters in [], which will match any one character from
the list. If the first character after the "[" is "^",
the class matches any character not in the list. Within a
list, the "-" character is used to specify a range, so
that a-z represents all characters between "a" and "z",
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inclusive. If you want "-" itself to be a member of a
class, put it at the start or end of the list, or escape
it with a backslash. (The following all specify the same
class of three characters: [-az], [az-], and [a\-z]. All
are different from [a-z], which specifies a class
containing twenty-six characters.)
Note also that the whole range idea is rather unportable
between character sets--and even within character sets
they may cause results you probably didn't expect. A
sound principle is to use only ranges that begin from and
end at either alphabets of equal case ([a-e], [A-E]), or
digits ([0-9]). Anything else is unsafe. If in doubt,
spell out the character sets in full.
Characters may be specified using a metacharacter syntax
much like that used in C: "\n" matches a newline, "\t" a
tab, "\r" a carriage return, "\f" a form feed, etc. More
generally, \nnn, where nnn is a string of octal digits,
matches the character whose ASCII value is nnn.
Similarly, \xnn, where nn are hexadecimal digits, matches
the character whose ASCII value is nn. The expression \cx
matches the ASCII character control-x. Finally, the "."
metacharacter matches any character except "\n" (unless
you use /s).
You can specify a series of alternatives for a pattern
using "|" to separate them, so that fee|fie|foe will match
any of "fee", "fie", or "foe" in the target string (as
would f(e|i|o)e). The first alternative includes
everything from the last pattern delimiter ("(", "[", or
the beginning of the pattern) up to the first "|", and the
last alternative contains everything from the last "|" to
the next pattern delimiter. For this reason, it's common
practice to include alternatives in parentheses, to
minimize confusion about where they start and end.
Alternatives are tried from left to right, so the first
alternative found for which the entire expression matches,
is the one that is chosen. This means that alternatives
are not necessarily greedy. For example: when matching
foo|foot against "barefoot", only the "foo" part will
match, as that is the first alternative tried, and it
successfully matches the target string. (This might not
seem important, but it is important when you are capturing
matched text using parentheses.)
Also remember that "|" is interpreted as a literal within
square brackets, so if you write [fee|fie|foe] you're
really only matching [feio|].
Within a pattern, you may designate subpatterns for later
reference by enclosing them in parentheses, and you may
refer back to the nth subpattern later in the pattern
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using the metacharacter \n. Subpatterns are numbered
based on the left to right order of their opening
parenthesis. A backreference matches whatever actually
matched the subpattern in the string being examined, not
the rules for that subpattern. Therefore,
(0|0x)\d*\s\1\d* will match "0x1234 0x4321", but not
"0x1234 01234", because subpattern 1 actually matched
"0x", even though the rule 0|0x could potentially match
the leading 0 in the second number.
WARNING on \1 vs $1
Some people get too used to writing things like:
$pattern =~ s/(\W)/\\\1/g;
This is grandfathered for the RHS of a substitute to avoid
shocking the sed addicts, but it's a dirty habit to get
into. That's because in PerlThink, the righthand side of
a s/// is a double-quoted string. \1 in the usual double-
quoted string means a control-A. The customary Unix
meaning of \1 is kludged in for s///. However, if you get
into the habit of doing that, you get yourself into
trouble if you then add an /e modifier.
s/(\d+)/ \1 + 1 /eg; # causes warning under -w
Or if you try to do
s/(\d+)/\1000/;
You can't disambiguate that by saying \{1}000, whereas you
can fix it with ${1}000. Basically, the operation of
interpolation should not be confused with the operation of
matching a backreference. Certainly they mean two
different things on the left side of the s///.
Repeated patterns matching zero-length substring
WARNING: Difficult material (and prose) ahead. This
section needs a rewrite.
Regular expressions provide a terse and powerful
programming language. As with most other power tools,
power comes together with the ability to wreak havoc.
A common abuse of this power stems from the ability to
make infinite loops using regular expressions, with
something as innocuous as:
'foo' =~ m{ ( o? )* }x;
The o? can match at the beginning of 'foo', and since the
position in the string is not moved by the match, o? would
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match again and again due to the * modifier. Another
common way to create a similar cycle is with the looping
modifier //g:
@matches = ( 'foo' =~ m{ o? }xg );
or
print "match: <$&>\n" while 'foo' =~ m{ o? }xg;
or the loop implied by split().
However, long experience has shown that many programming
tasks may be significantly simplified by using repeated
subexpressions which may match zero-length substrings,
with a simple example being:
@chars = split //, $string; # // is not magic in split
($whitewashed = $string) =~ s/()/ /g; # parens avoid magic s// /
Thus Perl allows the /()/ construct, which forcefully
breaks the infinite loop. The rules for this are
different for lower-level loops given by the greedy
modifiers *+{}, and for higher-level ones like the /g
modifier or split() operator.
The lower-level loops are interrupted when it is detected
that a repeated expression did match a zero-length
substring, thus
m{ (?: NON_ZERO_LENGTH | ZERO_LENGTH )* }x;
is made equivalent to
m{ (?: NON_ZERO_LENGTH )*
|
(?: ZERO_LENGTH )?
}x;
The higher level-loops preserve an additional state
between iterations: whether the last match was zero-
length. To break the loop, the following match after a
zero-length match is prohibited to have a length of zero.
This prohibition interacts with backtracking (see the
section on Backtracking), and so the second best match is
chosen if the best match is of zero length.
Say,
$_ = 'bar';
s/\w??/<$&>/g;
results in "<<b><><a><><r><>">. At each position of the
string the best match given by non-greedy ?? is the zero-
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length match, and the second best match is what is matched
by \w. Thus zero-length matches alternate with one-
character-long matches.
Similarly, for repeated m/()/g the second-best match is
the match at the position one notch further in the string.
The additional state of being matched with zero-length is
associated to the matched string, and is reset by each
assignment to pos().
Creating custom RE engines
Overloaded constants (see the overload manpage) provide a
simple way to extend the functionality of the RE engine.
Suppose that we want to enable a new RE escape-sequence
\Y| which matches at boundary between white-space
characters and non-whitespace characters. Note that
(?=\S)(?<!\S)|(?!\S)(?<=\S) matches exactly at these
positions, so we want to have each \Y| in the place of the
more complicated version. We can create a module customre
to do this:
package customre;
use overload;
sub import {
shift;
die "No argument to customre::import allowed" if @_;
overload::constant 'qr' => \&convert;
}
sub invalid { die "/$_[0]/: invalid escape '\\$_[1]'"}
my %rules = ( '\\' => '\\',
'Y|' => qr/(?=\S)(?<!\S)|(?!\S)(?<=\S)/ );
sub convert {
my $re = shift;
$re =~ s{
\\ ( \\ | Y . )
}
{ $rules{$1} or invalid($re,$1) }sgex;
return $re;
}
Now use customre enables the new escape in constant
regular expressions, i.e., those without any runtime
variable interpolations. As documented in the overload
manpage, this conversion will work only over literal parts
of regular expressions. For \Y|$re\Y| the variable part
of this regular expression needs to be converted
explicitly (but only if the special meaning of \Y| should
be enabled inside $re):
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use customre;
$re = <>;
chomp $re;
$re = customre::convert $re;
/\Y|$re\Y|/;
SEE ALSO
the section on Regexp Quote-Like Operators in the perlop
manpage.
the section on Gory details of parsing quoted constructs
in the perlop manpage.
the pos entry in the perlfunc manpage.
the perllocale manpage.
Mastering Regular Expressions (see the perlbook manpage)
by Jeffrey Friedl.
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